使用opencv截取旋转框目标
使用opencv截取旋转框目标
- 1、第一种方法
- 2、第二种方法
- 3、两种方法的简单对比
- 4、opencv 最小面积矩形返回角度的理解
- 4.1、version4.2之前
- 4.1、version4.2之后
本文列举了两种方法，使用的数据如图,用的是改版rolabelimg标注的
标注文件有四个点的坐标：
1、第一种方法
总体思路是，找最小面积矩形，接着旋转，最后crop
import cv2
import numpy as np
import matplotlib.pyplot as plt
def crop_rect(img, rect):
# get the parameter of the small rectangle
center, size, angle = rect[0], rect[1], rect[2]
center, size = tuple(map(int, center)), tuple(map(int, size))
# get row and col num in img
height, width = img.shape[0], img.shape[1]
# calculate the rotation matrix
M = cv2.getRotationMatrix2D(center, angle, 1)
# rotate the original image
img_rot = cv2.warpAffine(img, M, (width, height))
# now rotated rectangle becomes vertical, and we crop it
img_crop = cv2.getRectSubPix(img_rot, size, center)
return img_crop, img_rot
cnts = []
labels=[]
with open('rodog.txt') as f:
lines = f.read().strip().splitlines()
for line in lines:
data = line.split()
cnt=list(map(int,data[:8]))
label=data[8]
cnts.append(cnt)
labels.append(label)
num=len(cnts)
plt.figure(figsize=(15,num*5))
for i,cnt in enumerate(cnts):
img = cv2.imread("rodog.jpeg")
cnt = np.reshape(cnt,[4,2])
# print("cnt:",cnt)
# find the exact rectangle enclosing the text area
# rect is a tuple consisting of 3 elements: the first element is the center
# of the rectangle, the second element is the width, height, and the
# third element is the detected rotation angle.
# Example output: ((227.5, 187.50003051757812),
# (94.57575225830078, 417.98736572265625), -36.982906341552734)
rect = cv2.minAreaRect(cnt)
print("rect: {}".format(rect))
# the order of the box points: bottom left, top left, top right,
box = cv2.boxPoints(rect)
box = np.int0(box)
print("box:",box)
# print("bounding box: {}".format(box))
cv2.drawContours(img, [box], 0, (255, 0, 0), 2)
# img_crop will the cropped rectangle, img_rot is the rotated image
img_crop, img_rot = crop_rect(img, rect)
plt.subplot(num,3,1+i*3)
plt.imshow(img)
plt.title('orig')
plt.subplot(num,3,2+i*3)
plt.imshow(img_rot)
plt.title('rotate')
plt.subplot(num,3,3+i*3)
plt.imshow(img_crop)
plt.title('crop')
# cv2.imwrite(f"orig_img_{i}.jpg", img)
# cv2.imwrite(f"rotate_img_{i}.jpg", img_rot)
# cv2.imwrite(f"cropped_img_{i}.jpg", img_crop)
# cv2.waitKey(0)
rect: ((370.5, 164.50001525878906), (140.75865173339844, 306.3152160644531), 43.54475784301758)
box: [[213 227]
[425 5]
[527 101]
[316 324]]
rect: ((266.9999694824219, 53.499996185302734), (38.984642028808594, 44.95772933959961), 24.22774314880371)
box: [[239 65]
[258 25]
[293 41]
[275 81]]
rect: ((277.5, 132.0), (533.65625, 161.2079315185547), 11.457330703735352)
box: [[ 0 157]
[ 32 0]
[555 106]
[523 264]]
显示是用的bgr图，没转rgb
这种方法目前还没有遇到问题，如果遇到问题，可能需要在原图上做pad，相应的标签文件也做好修改再进行处理
2、第二种方法
思路是先找最小矩形，接着透视变换得到目标图。
import cv2
import numpy as np
import matplotlib.pyplot as plt
cnts = []
labels=[]
with open('rodog.txt') as f:
lines = f.read().strip().splitlines()
for line in lines:
data = line.split()
cnt=list(map(int,data[:8]))
label=data[8]
cnts.append(cnt)
labels.append(label)
num=len(cnts)
plt.figure(figsize=(10,num*5))
for i,cnt in enumerate(cnts):
img = cv2.imread("rodog.jpeg")
cnt = np.reshape(cnt,[4,2])
# print("cnt:",cnt)
# find the exact rectangle enclosing the text area
# rect is a tuple consisting of 3 elements: the first element is the center
# of the rectangle, the second element is the width, height, and the
# third element is the detected rotation angle.
# Example output: ((227.5, 187.50003051757812),
# (94.57575225830078, 417.98736572265625), -36.982906341552734)
rect = cv2.minAreaRect(cnt)
# print("rect: {}".format(rect))
# the order of the box points: bottom left, top left, top right,
# bottom right
box = cv2.boxPoints(rect)
box = np.int0(box)
# print('box:',box)
# print("bounding box: {}".format(box))
cv2.drawContours(img, [box], 0, (0, 255, 0), 2)
# get width and height of the detected rectangle
width = int(rect[1][0])
height = int(rect[1][1])
# print("width,height:",width,height)
src_pts = box.astype("float32")
# coordinate of the points in box points after the rectangle has been
# straightened
dst_pts = np.array([[0, height-1],
[0, 0],
[width-1, 0],
[width-1, height-1]
], dtype="float32")
# the perspective transformation matrix
M = cv2.getPerspectiveTransform(src_pts, dst_pts)
# directly warp the rotated rectangle to get the straightened rectangle
warped = cv2.warpPerspective(img, M, (width, height))
# cv2.imwrite("crop_img.jpg", warped)
# cv2.waitKey(0)
plt.subplot(num,2,1+i*2)
plt.imshow(img)
plt.title('orig')
plt.subplot(num,2,2+i*2)
plt.imshow(warped)
plt.title('crop')
3、两种方法的简单对比
img_crop.shape
(161, 533, 3)
warped.shape
(161, 533, 3)
两种方式看效果是一样的，图像尺寸也一样，但要对比像素值，还是不一样，如下代码，绝对误差大于20有4.56%
try:
np.testing.assert_allclose(img_crop,warped,atol=20)
except Exception as e:
print(e)
Not equal to tolerance rtol=1e-07, atol=20
Mismatched elements: 11739 / 257439 (4.56%)
Max absolute difference: 255
Max relative difference: 255.
x: array([[[255, 0, 0],
[255, 0, 0],
[237, 15, 18],...
y: array([[[ 0, 255, 0],
[ 0, 255, 0],
[ 0, 255, 0],...
4、opencv 最小面积矩形返回角度的理解
center, size, angle=cv2.minAreaRect(points)
points就是一系的（x,y)的点，center,size,angle分别是最小矩形的中心点，宽高，及angle。对于opencv的这个角度的理解，这里简单写一些，实际是与opencv版本有关，以opencv4.2为分界
4.1、version4.2之前
https://blog.csdn.net/weixin_43229348/article/details/125986969 (https://theailearner.com/tag/cv2-minarearect/) 参考这个博客就好，一句话说，就是x轴逆时针转，接触到的第一条边就是宽边w(不在意长短）,转的过程就是角度从0到-90 ，不包括0。
那么最小面积矩形的四个点及顺序是啥，用以下代码获取：
rect = CV2.minAreaRect(cnt)
box = cv2.boxPoints(rect)
box就是四个点的坐标，我们会用这四个点做旋转或透视变换都是需要的。那么顺序是什么呢？
可以理解为x轴与w边相交，箭头反方向的点为起点，接着顺时针。
4.1、version4.2之后
x轴顺时针转，接触到的第一条边就是宽边w(不在意长短）,转的过程就是角度从0到90 ，不包括0。x轴也与4.2之前的相反。
点顺序如下：
可以理解为x轴与w边相交，箭头同方向的点为起点，接着顺时针。
本文另一篇参考文章：https://jdhao.github.io/2019/02/23/crop_rotated_rectangle_opencv/#fn:2